elevenlang
New member
how is static field calculated for LR monsters
will it reduce less than 25% each time?
for no LI monster
will it reduce less than 25% each time?
for no LI monster
It's definately less. If it's not altered by resistance, it would work like this:
for a 1000 hp monster (stops at 333hp in nm, 500 in hell):
after 1rst SF: 750 hp
2 : 562.5 hp
3 : 421.875 hp in nm, 500 in hell
4 : 333 hp in nm, 500 in hell
Meaning that if lightning resistance is not calculated in, you would have any actboss under or at half life with 3 SF (which is not the case ofc). Also, lightning immune monsters are monsters with (more than) 100% lightning resistance in the game mechanics. That's why cold mastery or conviction can break those immunities. The fact that it doesn't work on any lightning immunes shows that it takes resistances into account at the normal rate. The formula should be something like:
damage = ((25*life/100)*((100-lightning resist)/100))
Disclaimer: this is out of the top of my head, didn't look anything up. I also didn't put in any lightning absorb, or any other PvP aspects.
Depends on what kind. There are immune monsters (says immune if you hoover them), but in hell some champions are immune due to minimum 50% resistance + FE, LE,... Those just have 100+ resistance, which can be lowered by skills and items.
If you try and static a hell LE unique, there is no damage, so resistance counts for SF.
Actually, the static cap in NM and hell doesn't stop static from damaging a monster to below the cap, it just prevents further casts of SF. So if a hell monster has 0 LR, you have no -ELR an the monster is at 5001 of 10 000 HP, a cast of SF will bring it to 3751 HP, not 5000.
LR reduces static damage the same way as any other lightning damage, except when conviction/Lower Resist brings their resist below 0. Then it gets calculated as 0. With -ELR it becomes much more complicated.