A rough HFQ-calculator v 0.9

d2lover

Well-known member
Guide Author
Oct 8, 2019
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I'm required to learn at home and this is what I spent my afternoon with.

I'm open to suggestions.
The language is c++.
compiled exe for win10: can't find a good site to upload, I will edit it later.
Sourceforge requires phonenumber and doesn't accept mine, but I filled it in correctly.

Code:
/*
Name of the program:            HFQ-Calculator
Purpose of the program:         This program's purpose is to calculate the expected time to get
                                a specific rune in Diablo 2 1.10+ via the Hellforge.
                                It is assumed, that you keep runes below Pul.
                                It also assumes that you can trade for example Ist vs 2 Mal.(due to incompetence from my part)
Who wrote this code and when:   d2lover, 7th August 2020
Version number:                 0.9
Assumed user input:             integers, letters
*/

#include <iostream>     // required for outputting text on screen and for reading the user's input
#include <limits>       // used for the "Press Enter to continue"-message
#include <vector>       // required to store the runeworth in Hel-runes in a vector

const std::string version_number = "V 0.9";
const std::string screen_clear_string = std::string ( 50, '\n' );
const std::vector<std::string> runes
{
    "Sol",
    "Shael",
    "Dol",
    "Hel",
    "Io",
    "Lum",
    "Ko",
    "Fal",
    "Lem",
    "Pul",
    "Um",
    "Mal",
    "Ist",
    "Gul",
    "Vex",
    "Ohm",
    "Lo",
    "Sur",
    "Ber",
    "Jah",
    "Cham",
    "Zod"};

const double runeworth_nm_in_pul    =(1.+2)/11;
const double runeworth_hell_in_pul  =(1.+2+4+8+16)/11;



// self explanatory
void press_enter_to_continue()
{
    std::cout << "Press ENTER to continue... " << std::flush;
    std::cin.ignore ( std::numeric_limits <std::streamsize> ::max(), '\n' );
}

// function that acts as a screen clear
void screen_clear()
{
    std::cout << screen_clear_string;
}


int get_target_rune()
{
    screen_clear();
    std::cout << "Enter the integer of the rune you want:\n";
    for(unsigned int i=0; i<runes.size();i++)
    {
        std::cout << runes[i]<<":"<<i<<"\n";
    }
    int target_rune=0;
    std::cin >> target_rune;
    return target_rune;
}

int get_number_of_rushees()
{
    screen_clear();
    std::cout << "Enter your number of rushees per HFQ-run:\n";
    int number_of_rushees=1;
    std::cin>>number_of_rushees;
    return number_of_rushees;
}

int get_time_per_run()
{
    screen_clear();
    std::cout << "Enter your time per run in minutes:\n";
    int time_per_run=1;
    std::cin>>time_per_run;
    return time_per_run;
}

void do_more_rounds();

void one_calculation()
{
    std::vector<int> runeworth_sol_to_zod(9,0);
    runeworth_sol_to_zod.push_back(1);//Pul
    runeworth_sol_to_zod.push_back(2);//Um
    runeworth_sol_to_zod.push_back(4);//Mal
    runeworth_sol_to_zod.push_back(8);//Ist
    runeworth_sol_to_zod.push_back(16);//Gul
    runeworth_sol_to_zod.push_back(32);//Vex
    runeworth_sol_to_zod.push_back(64);//Ohm
    runeworth_sol_to_zod.push_back(128);//Lo
    runeworth_sol_to_zod.push_back(256);//Sur
    runeworth_sol_to_zod.push_back(512);//Ber
    runeworth_sol_to_zod.push_back(1024);//Jah
    runeworth_sol_to_zod.push_back(2048);//Cham
    runeworth_sol_to_zod.push_back(4096);//Zod
    std::cout << "Welcome to HFQ-Calculator "<<version_number<<"\n";
    press_enter_to_continue();
    int target=get_target_rune();
    int rushees=get_number_of_rushees();
    int time=get_time_per_run();
    double expected_runs=0;
    if (target<3) // runes Sol-Dol
    {
        expected_runs=11./rushees;
    }
    else if (target>2 && target<9) // runes Hel-Lem
    {
        expected_runs=11./(rushees*2);
    }
    else
    {
        expected_runs=runeworth_sol_to_zod[target]/((runeworth_nm_in_pul+runeworth_hell_in_pul)*rushees);
    }

    std::cout << "You need to do on average "<< expected_runs<<" runs and it will take you " << expected_runs*time<<" minutes.\n";
    void do_more_rounds();
}

void do_more_rounds()
{
    one_calculation();
    std::cout << "Do you want to calculate another rune? (y/n)\n";
    char yes_no=' ';
    std::cin >> yes_no;
    if(yes_no=='y')
    {
        one_calculation();
    }
    else
    {
        std::cout << "Bye\n";
    }
}

int main()
{
    do_more_rounds();
    return 0;
}
 
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